JavaScript spying on bunyan log - NodeJS

Is there any way in which I can spy on the bunyan log to ensure I print out what I expect?

MyFile.js

const bunyan = require('bunyan');
const log = bunyan.createLogger({name: 'FailureAuditService'});

class someClass {
   someFunct() {
     if(x) {
        log.warn('something happened');
     }
   }
}

Test

const service = require(../MyFile);

describe('test something', () => {
    it('Will test the bunyan log', res => {
       let consoleLog = sinon.spy(log, 'createLogger');
       let x = true;

       service.someClass(x).then(res => {
          let expected = 'something happened';
          consoleLog.should.equal(expected);
       });
    });
})
Answer:1

I worked around this with the following:

const mockReq = require('mock-require);

...

let infoStub = sinon.stub();
let warnStub = sinon.stub();

logStubs = {
   info: infoStub,
   warn: warnStub
   // any other log methods you wish to use
};

mockReq('bunyan', {
   createLogger() {
      return logStubs;
   }
});

...

I then used to mockReq.reRequire() function later on to reset the cache of the service I was wanting to mock.

To assert the actual content of the logs:

let infoLog = infoStub.firstCall.args[0];
let warnLog = warnStub.firstCall.args[0];

With this, I could assert them to equal whatever I expected.

Answer:2

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