JavaScript passing argument to map function passing argument function c,passing argument function php,passing function

I have code like:

var addX = (e) => return e+1;

I am calling like:

[1,2,3].map(addX);

Can I make "1" dynamic? Like:

[1,2,3].map(addX(2)); //this wont work, in this case it should add 2
Answer:1

You need a closure over e and return a function with one parameter for the callback.

var addX = x => v => x + v;

console.log([1, 2, 3].map(addX(2)));
Answer:2

You can use currying like this:

var addX = n => e => e + n;
console.log([1,2,3].map(addX(2)));
console.log([1,2,3].map(addX(10)));
Answer:3

You can create a function to return a function that takes your add amount.

Here is an example below.

var addX = (addbit) => (e) => e + addbit;

console.log([1,2,3].map(addX(2)));
Answer:4

I would do something like this :)

var addX = (e) =>   e+1;

[1,2,3].map(num => addX(num))
Answer:5

Several utility libraries like Lodash, Underscore, and Ramda provide a curry() utility function that takes a function and returns a new version of that function that can take the same arguments one at a time, a few at a time, or all at once.

This means that you can create an add function that can either add two numbers right away add(4, 5) or that can "pre-bake" a function with one of the values included: const increment = add(1); console.log(increment(5));

const add = _.curry((x, y) => x + y);

console.log(add(6, 7));

console.log([1,2,3].map(add(10)));
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
Answer:6

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