JavaScript document.getElementsByTagName('*') does not recognize SVG TAG and give console error document getelementsbytagname java,document getelementsbytagname innerhtml,document getelementsbytagname w3schools,document

First of all, document.getElementsByTagName(...), document.querySelector(...) and document.querySelectorAll(...) all DO recognise SVG.

The error you get from your code is not because of that. The problem is because you use .trim() on an object instead of string. Well, I get the confusion.

For normal elements, .className returns a string. For SVG, however, .className returns a SVGAnimatedString object.

var div = document.querySelector('div');
var svg = document.querySelector('svg');

console.log('className of div: ', div.className);
console.log('className of svg: ', svg.className);
<div class="normal"></div>
<svg class="special"></svg>
Answer:1

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