JavaScript Sort two arrays from object depending on one of those arrays in Javascript sort array from smallest to largest javascript,sort array from

For each object, construct a Map whose keys are fruit strings and values are the associated original number in the c array. Sort the c array, then sort the b array based on the difference between the items in the map:

const arr = [
   {a: 1, b: ['apple', 'banana', 'orange', 'mango'], c: [42, 7, 18, 5]},
   {a: 2, b: ['apple', 'banana', 'orange', 'mango'], c: [4, 101, 88, 3]},
   {a: 3, b: ['apple', 'banana', 'orange', 'mango'], c: [14, 10, 5, 12]},
   {a: 4, b: ['apple', 'banana', 'orange', 'mango'], c: [99, 2, 105, 101]}
];
Object.values(arr).forEach(({ b, c }) => {
  const fruitValues = c.reduce(
    (map, num, i) => map.set(b[i], num),
    new Map()
  );
  c.sort((a, b) => a - b);
  b.sort((a, b) => fruitValues.get(a) - fruitValues.get(b));
});
console.log(arr);

Answer:1

You can zip elements of b and c together, sort them by the c element, then unpack them back. With this method, only one sort is necessary, even if you are sorting multiple lists.

const arr = [
   {a: 1, b: ['apple', 'banana', 'orange', 'mango'], c: [42, 7, 18, 5]},
   {a: 2, b: ['apple', 'banana', 'orange', 'mango'], c: [4, 101, 88, 3]},
   {a: 3, b: ['apple', 'banana', 'orange', 'mango'], c: [14, 10, 5, 12]},
   {a: 4, b: ['apple', 'banana', 'orange', 'mango'], c: [99, 2, 105, 101]}
];
Object.values(arr).forEach(row => {
  let sorting = row.b.map((e, i, a) => [e, row.c[i]]);
  sorting.sort(([b1, c1], [b2, c2]) => c1 - c2);
  row.b = sorting.map(([e, ]) => e);
  row.c = sorting.map(([, e]) => e);
});
console.log(arr);

Answer:2

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