JavaScript Sort array of object if value exists sort array object javascript,sort array object javascript by value,

Below is my sort function but I want to display the ones with a code to be at the top. I want to sort my array of objects by code, then by description. Right now, the items without a code is being placed at the top of the order.

data = [
 {
  code: "1.1",
  description: "aaa"
 },
 {
  code: "",
  description: "bbb"
 },
 {
  code: "1.2",
  description: "ccc"
 }
]


  let sortedData = data.sort(function(a, b) {
    let codeA = a.code
    let codeB = b.code
    let descriptionA = a.description.toLowerCase()
    let descriptionB = b.description.toLowerCase()

    if (codeA < codeB) return -1
    if (codeA > codeB) return 1
    if (descriptionA < descriptionB) return -1
    if (descriptionA > descriptionB) return 1
    return 0
  })

  return sortedData

Current order:

["bbb", "aaa", "ccc"]

Expected order:

["aaa", "ccc", "bbb"]

Answer:1

One way to make "" appear at the end is just to prefix the compare values, so if the code is "", the value becomes "B", if it's 1.1 it become A1.1, so A1.1 < B..

Doing this is also very easy to modify to do all sort of fancy sorting, eg. Lets say you wanted to sort alphabetically, but wanted all K's at the start, and all B's at the end, strange thing to do. But very easy to make happen. I suppose you could call it sorting with exceptions.

Here is a working example.

const data = [
 {
  code: "1.1",
  description: "aaa"
 },
 {
  code: "",
  description: "bbb"
 },
 {
  code: "1.2",
  description: "ccc"
 }
];

data.sort((
  { code: code1, description: desc1 },
  { code: code2, description: desc2 }
) => {
  code1 = (code1 === "" ? "B" : "A") + code1;
  code2 = (code2 === "" ? "B" : "A") + code2;
  return code1.localeCompare(code2) ||
    desc1.localeCompare(desc2);
});


console.log(data);

Answer:2

Your test case is a little lax and makes it hard to spot some bugs. You are usually better off using localeCompare to compare strings. You can make a case for two very plain, but readable if statements followed by a localeCompare of the strings:

Here's a few extra test cases

let data = [{
    code: "1.1",
    description: "ddd"
  },
  {
    code: "1.101",
    description: "ccc"
  },
  {
    code: "",
    description: "eee"
  },
  {
    code: "1.2",
    description: "De"
  },
  {
    code: "1.1",
    description: "aaa"
  },
  {
    code: "",
    description: "bbb"
  },
  {
    code: "1.2",
    description: "ccc"
  },
  {
    code: "1.2",
    description: "AbcD"
  }
]

data.sort((a, b) => {
  if (a.code && !b.code) return -1
  if (b.code && !a.code) return 1

  return a.code.localeCompare(b.code) || a.description.localeCompare(b.description)
})
console.log(data)

Answer:3

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