JavaScript Return object(s) in array with highest property value per group return objects array,return array objects php,return array objects

I have an array containing several objects similar to the following:

{person: {name: "Steve", id: 1}, role: 1}
{person: {name: "Phil", id: 2}, role: 1}
{person: {name: "Steve", id: 1}, role: 3}
{person: {name: "Phil", id: 2}, role: 6}

My intention is to return an array of the same type, but I'd like to return only one object per "person" with their highest role.

I understand the following will give me a single object with the highest role.

array.reduce((prev, cur) => prev.role > cur.role ? prev : cur);

How do I return each unique person and their corresponding highest role as a new array?

Like so:

{person: {name: "Steve", id: 1}, role: 3}
{person: {name: "Phil", id: 2}, role: 6}
Answer:1

You need to collect the objects and if you have already one with the same id check the role and take the greater one.

var data = [{ person: { name: "Steve", id: 1 }, role: 1 }, { person: { name: "Phil", id: 2 }, role: 1 }, { person: { name: "Steve", id: 1 }, role: 3 }, { person: { name: "Phil", id: 2 }, role: 6 }],
    grouped = data.reduce((r, o) => {
        var index = r.findIndex(({ person: { id } }) => id === o.person.id);
        if (index === -1) {
            r.push(o);
            return r;
        }
        if (r[index].role < o.role) {
            r[index] = o;
        }
        return r;    
    }, []);

console.log(grouped);
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Answer:2

Group the items by person.id with Array.reduce(), but for each id store only the object with the highest role. Convert back to array using Object.values():

const data = [{ person: { name: "Steve", id: 1 }, role: 1 }, { person: { name: "Phil", id: 2 }, role: 1 }, { person: { name: "Steve", id: 1 }, role: 3 }, { person: { name: "Phil", id: 2 }, role: 6 }];

const result = Object.values(data.reduce((r, o) => {
  const id = o.person.id;
  
  if(!r[id] || r[id].role < o.role) r[id] = o;
  
  return r;
}, []));

console.log(result);
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Answer:3

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