JavaScript Passing Form Field Data Only If Data Is Entered In Another Field In Same Form passing value to hidden form field jquery,how to get

You can check below mentioned solution

<?php if($_POST['phoneNumber'] != NULL || $_POST['phoneNumber'] != ''): ?>
      <div class="numberWrapper">
    <span class="phoneIcon"><?php $phoneIcon = ($_POST['phoneIcon']); echo  $phoneIcon;?>&nbsp;</span>
    <span class="phoneNumber"><?php $phoneNumber = ($_POST['phoneNumber']); echo  $phoneNumber;?></span>
    </div>
<?php endif; ?>
Answer:1
Check whether telephone number is posted and not equal to null.
    <?php ob_start(); ?> 

    <!DOCTYPE html>
    <html>
    <head>
    <title>Upload Results</title>

    <style>

    body{margin:0;}
    .numberWrapper {margin: 100px 0px 0px 30px; }
    .phoneIcon {font-size: 20px;}
    .phoneNumber {font-family:Arial, Helvetica, sans-serif; font-size:12pt;}

    </style>

    </head>
    <body>
<?php if( isset($_POST['phoneIcon']) && $_POST['phoneIcon'] != '')
    { ?>
    <div class="numberWrapper">

    <span class="phoneIcon"><?php $phoneIcon = ($_POST['phoneIcon']); echo  $phoneIcon;?>&nbsp;</span>

    <span class="phoneNumber"><?php $phoneNumber = ($_POST['phoneNumber']); echo  $phoneNumber;?></span>
    </div>
<?php } ?>


    </body>
    </html>

    <?php echo ''; (ob_get_contents()); ?>
Answer:2

try this:

<?php if(!empty($_POST['phoneNumber'])){ ?>
    <span class="phoneIcon"><?php $phoneIcon = ($_POST['phoneIcon']); echo  $phoneIcon;?>&nbsp;</span>
    <?php } ?>
    <span class="phoneNumber"><?php $phoneNumber = ($_POST['phoneNumber']); echo  $phoneNumber;?></span>
Answer:3

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