JavaScript Javascript remove all empty innerHTML elements children javascript remove empty string from array,javascript remove empty lines,

Problem with your code is when you remove items, children will actually reduce, so you are shifting everything down one index. People typically loop backwards to stop this error.

Perosnally I would just use a empty pseudo class selector with querySelectorAll and a forEach loop.

var emptyAnchors = document.querySelectorAll("li > a:empty")
emptyAnchors.forEach(function (a) {
  a.parentNode.remove()
})
<ul class="parent">
  <li>
    <a target='_blank' href="">One</a>
  </li>
  <li>
    <a target='_blank' href=""></a>
  </li>
  <li>
    <a target='_blank' href=""></a>
  </li>
  <li>
    <a target='_blank' href="">Two</a>
  </li>
  <li>
    <a target='_blank' href="">Three</a>
  </li>
</ul>
Answer:1

When you're looping through a list and removing things, it throws the index off. Loop through it backwards instead:

let lis = document.querySelector(".parent").children

for (let i = lis.length - 1; i >= 0; i--) {
    if (lis[i].firstElementChild.innerHTML === "") {
        lis[i].remove()
    } 
}
<ul class="parent">
    <li><a target='_blank' href="">One</a></li>
    <li><a target='_blank' href=""></a></li>
    <li><a target='_blank' href=""></a></li>
    <li><a target='_blank' href="">Two</a></li>
    <li><a target='_blank' href="">Three</a></li>
</ul>
Answer:2

<script>
//list of all anchor elements in your HTML DOM
onload = function() {
  var anchors = document.getElementsByTagName("a");
  for(var i = 0; i < anchors.length; i++) {
    var anchor = anchors[i];
    if(anchor.innerHTML == "") {
      anchor.parentNode.removeChild(anchor); //removes the anchor
    }
  }
}
</script>
<a target='_blank' href="x">Something</a>
<a target='_blank' href="x"></a>
<a target='_blank' href="x">Something</a>
<a target='_blank' href="x">Something</a>
Answer:3

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