JavaScript Javascript Avoid getting null after deleting objects from array

You can use the following code,
Here you can simply use the .splice() which will remove element from your array. Don't need to use multiple forEach().

var json_data = [
  [{
    value: "value1",
    formattedValue: "value1"
  }, {
    value: "Unwanted part 3",
    formattedValue: "Unwanted part 3"
  }, {
    value: 2831.8,
    formattedValue: "283,180.00 %"
  }],
  [{
    value: "value1",
    formattedValue: "value1"
  }, {
    value: "Unwanted part 2",
    formattedValue: "Unwanted part 2"
  }, {
    value: 349.1111111111111,
    formattedValue: "34,911.11 %"
  }],
  [{
    value: "value2",
    formattedValue: "value2"
  }, {
    value: "Unwanted part 1",
    formattedValue: "Unwanted part 1"
  }, {
    value: 3.3703703703703702,
    formattedValue: "337.04 %"
  }]
];

document.getElementById("before").innerHTML = JSON.stringify(json_data);

for (i = 0; i < json_data.length; i++) {
  let items = json_data[i];
  console.log("ITEMS  ===>", items);
  items.splice(1, 1);
}

document.getElementById("after").innerHTML = JSON.stringify(json_data);
<h1>before</h1>
<div id="before"></div>
<h1>after </h1>
<div id="after"></div>
Answer:1

delete won't do what you want it to in this case, it will always replace an array entry with an empty position as I believe it handles the Array like an object (so your length property won't update either).

You nearly have it in your commented out section I believe. Instead of:

 return item.subItemToBeRemovedId.splice(index, 1);

use:

items.splice(subItemToBeRemovedId, 1);
return items;

Splice will mutate your Array, which you can then return.

Answer:2

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