JavaScript JS Closure and Function Parameters javascript closure function parameters,function closure argument

The following snippet is from "Example 5" from this thread on JS and closure. Alternatively, this other thread sort of gets at what I'm curious about.

function buildList(list) {
    var result = [];
    for (var i = 0; i < list.length; i++) {
        var item = 'item' + i;
        result.push( function() {alert(item + ' ' + list[i])} );
    }
    return result;
}

function testList() {
    var fnlist = buildList([1,2,3]);
    for (var j = 0; j < fnlist.length; j++) {
        fnlist[j]();
    }
}

The thread this snippet is from says the output is: "item3 undefined"x3. I understand why "item3" is printed all three times, but I don't understand why list[i] is undefined.

My Question: since list is a parameter of buildList, does that mean it's not a part of the closure of the anonymous function within result.push? If there were a variable within buildList (otherList) which was set to list (and the anonymous function used otherList[i]), would otherList[i] be in the closure? (Therefore instead of "item3 undefined"x3, the output would be "item3 3"x3).

Answer:1

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